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dem82 [27]
3 years ago
14

Please help

Physics
1 answer:
NikAS [45]3 years ago
7 0
D, Metamorphism
-Metamorphic rocks are any rocks that change into another rock when subjected to high heat and pressure.
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Paula has walked in a straight line, 30.5° north of west, for 1650 meters. How far south and east should she walks to return to
olchik [2.2K]
The answer is A.
Sy = 1650 x sin30.5 = 837.4 m toward south
Sx = 1650 x cos30.5 = 1421.7 m toward east
8 0
2 years ago
A viscous fluid is flowing through two horizontal pipes. They have the same length, although the radius of one pipe is three tim
Rudik [331]

The conservation of the mass of fluid through two sections (be they A1 and A2) of a conduit (pipe) or current tube establishes that the mass that enters is equal to the mass that exits. Mathematically the input flow must be the same as the output flow,

Q_1 = Q_2

The definition of flow is given by

Q =VA

Where

V = Velocity

A = Area

The units of the flow of flow are cubic meters per second, that is to say that if there is a continuity, the volume of input must be the same as that of output, what changes if the sections are modified are the proportions of speed.

In this way

Q_A = Q_B

Q_B = 2.94*10^2 m^3/s

7 0
3 years ago
Explain why xrays are used to take images of inside the body but UV isnt
Sidana [21]

Answer:

X-rays go all the way through the body, but ultraviolet rays do not.

Explanation:

An x-ray will show inside the body, but uv light isn't strong enough to go all the way through the body.

6 0
2 years ago
A rocket sled accelerates from rest for a distance of 645 m at 16.0 m/s2. A parachute is then used to slow it down to a stop. If
inessss [21]

Answer:

the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake

Explanation:

This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period

          v² = v₀² + 2 a₁ x

indicate that the initial velocity is zero

          v² = 2 a₁ x

let's calculate

          v = \sqrt {2 \ 15.0 \ 645}

          v = 143.666 m / s

now for the second interval let's find the distance it takes to stop

          v₂² = v² - 2 a₂ x₂

in this part the final velocity is zero (v₂ = 0)

         0 = v² - 2 a₂ x₂

         x₂ = v² / 2a₂

let's calculate

         x₂ = \frac{ 143.666^2 }{2 \  18.2}

         x₂ = 573 m

as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake

3 0
2 years ago
Make a Book Quilt Project about the book Bud, Not Buddy
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Answer:

Explanation:

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8 0
2 years ago
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