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Montano1993 [528]
3 years ago
15

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95​% of all males.​ (Accommodating 100

% of males would require very wide seats that would be much too​ expensive.) Men have hip breadths that are normally distributed with a mean of 14.2 in. and a standard deviation of 0.9 in. Find Upper P 95. That​ is, find the hip breadth for men that separates the smallest 95​% from the largest 5​%.
Physics
1 answer:
horsena [70]3 years ago
3 0

Answer:

The answer is 15.68 in

Explanation:

X~N(μ=14.2; σ=0.9)

P(X\leq a)=0.95

I want to find "a", so:

P(0\leq X\leq a)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{a-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}

Z~N(0; 1)

P(0\leq X\leq a)=P(\frac{0-14.2}{0.9} \leq Z}\leq \frac{a-14.2}{0.9})=\phi(\frac{a-14.2}{0.9})-\phi(-15.78)=0.95

Φ(-15.78)≅0

\phi(\frac{a-14.2}{0.9})=0.95

Based on the Standard Normal table

\phi(Z_{a} )=0.95 if Z_{a}=1.64485

(a-14.2)/0.9=1.64485, then a=15.68

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Explanation:

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Answer:

Part 1

Stationary

Part 2

20 Newtons

Part 3

Force

Part 4

4.0 m/s²

Part 5

Normal

Part 6

Cart m

Part 7

The gravitational force is less than magnetic force

Explanation:

Part 1

The position time graph of the object is an horizontal straight line passing across the top of the position 3 boxes vertically up from the origin

As the time increases by the units of number boxes to the left, the position of the object does not change and remains at the 3 boxes up above the origin, therefore, the object is stationary

Part 2

By Newton's third law of motion, the action action obtained from a force is equal to the reaction given to the force, therefore, we have;

The force exerted by the student on the scale = The force exerted by the scale on the student = 20 N

Part 3

A force is a the directional push on an object or pull from the object as a form of interaction with another object which tends to alter or maintain the motion of the object

Part 4

The given parameters are'

The mass of block A = 1.0 kg

The mass of block B = 2.0 kg

Both blocks, "A" and "B" are initially at rest

The applied horizontal force, F = 12-N

The nature of the surface over which the blocks move = Smooth surface

Force, F = Mass, m × Acceleration, a

F = m × a

The blocks two blocks experience a common acceleration, a

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m = 3.0 kg

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Part 5

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Part 7

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