Solution:
As, You have Written Polygon ABCD is a rectangle.
It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).
Join any of the diagonal of Rectangle either AC or B D.
In Right Δ ABC , Right angled at B
---(1)
In Right Δ ADC , Right angled at D
---(2)
Adding (1) and (2) that is LHS to LHS and RHS to RHS
Ar( Δ ABC) +Ar( Δ ADC)
So, Area of Rectangle= Product of any two Adjacent Sides
Answer:
Step-by-step explanation:
Area of square= l×l
Area of square= 6mm × 6mn
Area if square = 36 mm²
Area of triangle 1= ½b ×h
Area of triangle 1= ½ (6mm)(8mm)
Area of triangle 1 = 24 mm²
Area of triangle 2 is the same as area of traingle 1 because they have the same base and hight
: . area of triangles is 48mm²
Area of the figure= Area of square + Area of triangles
A of figure = 36+48
A of figure = 84 mm²
Option 2
Use trapezium formula
Area of trapezium= (a+b)/2 * h
a=6 mm (base)
b=8+6=14 mm (Base)
h= 6mm (height)
Therefore the area of triangle= 24mm² as calculated in option 1
Area of the figure= Area of trapezium +Area of triangle
Area of figure = 60+24
= 84 mm²