$7(x-3)^2-4(x-3)-3\\\\substitute\ t=x-3,\ then\ we\ have\\\\7t^2-4t-3\\\\a=7;\ b=-4;\ c=-3\\\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot7\cdot(-3)=16+84=100\\\\t_1=\dfrac{-b-\sqrt\Delta}{2a};\ t_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\t_1=\dfrac{-(-4)-10}{2\cdot7}=\dfrac{4-10}{14}=\dfrac{-6}{14}=-\dfrac{3}{7}\\\\t_2=\dfrac{-(-4)+10}{2\cdot7}=\dfrac{4+10}{14}=\dfrac{14}{14}=1\\\\7t^2-4t-3=7\left(t+\dfrac{3}{7}\right)(t-1)=(7t+3)(t-1)\\\\=(7(x-3)+3)(x-3-1)=(7x-21+3)(x-4)\\\\=\boxed{(7x-18)(x-4)}$

7 0

3 years ago

Which is the equation of the line?

sasho [114]

A. -5x + 3y = 15 is your answer. this is because the slope is 5/3 and the y-intercept is 5 so you plot those onto the graph and this shows it.

hope this helps, God bless!

4 0

3 years ago

20 plants were mesured and their heights recorded in cm. here are the heights: 13.2 17 4.8 15.6 12 8.5 11.1 9.9 17.4 14.7 12.6 7

GaryK [48]

Answer:

hi there I have.

Step-by-step explanation:

the train leaves at 6.30. unfortunately the flight is delayed.

7 0

3 years ago