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loris [4]
3 years ago
8

Will give brainiest!!! asap!! not hard plzz!! What is the rule for the function shown in the table?

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

It's

Step-by-step explanation:

snow_tiger [21]3 years ago
6 0

Answer:

None of the above work out,so its 1.

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What property is shown 4/5 + (-4/5) =0
mina [271]

Answer:

Inverse property of addition

Step-by-step explanation:

When you add two opposite numbers (4/5 is the opposite of [-4/5]) the answer is always zero.

3 0
3 years ago
If the surface area of a cube is 294, whats the length of the cube?
tatyana61 [14]

Answer:

7

Step-by-step explanation:

Total number of surfaces of cube are 6.

Each surface is square.

And area of square is (side)^2

That means, total surface area will be 6 * (side)^2

From question,

294 = 6 * (side)^2 ( Surface area given)

=> 294 ÷ 6 = ( side) ^2

=> 49 = side^2

=> √49 = side

=> 7 = side

So, length of edge of cube is 7

7 0
3 years ago
Word Problem: The Merryweathers want a new square rug for their living room. If the living room is 20 ft x 16 ft, will the squar
forsale [732]
Square root  of 289  =  17 ft

so this rug would not fit the room because  one side is 16 ft long.
5 0
3 years ago
Linda has two cats. The difference in weight of her Maine Coon and Siderian is at least 6 pounds. Linda's Siberian has a height
Simora [160]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
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