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disa [49]
3 years ago
14

In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.

If there are 45 students in her class, how many have both a dog and a cat as pets?
Mathematics
2 answers:
harina [27]3 years ago
7 0
I believe 36 have both dogs and cats as pets
Travka [436]3 years ago
5 0

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

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jacob wants to buy packets of fruit juice. on tuesday, he buys 8 packets of orange and 6 packets of Apple the packets make a tot
ioda

Answer:

Each packet of orange can make 2 cups of juice and each packets of Apple can make 3 cups of juice.

Step-by-step explanation:

Let number of cups of juice in each packet of orange be 'x'.

Let number of cups of juice in each pack of apples be 'y'.

Given:

On Tuesday;

Number of packets of oranges = 8

Number of packets of apples = 6 packets.

Amount of fruit juice = 34 cups

So we can say that;

Amount of fruit juice is equal to sum of Number of packets of oranges multiplied by number of cups of juice in each packet of orange and Number of packets of apples multiplied by number of cups of juice in each pack of apples.

framing in equation form we get;

8x+6y=34 \ \ \ \ equation \ 1

On Wednesday;

Number of packets of oranges = 14

Number of packets of apples = 6

Amount of fruit juice = 46 cups

So we can say that;

Amount of fruit juice is equal to sum of Number of packets of oranges multiplied by number of cups of juice in each packet of orange and Number of packets of apples multiplied by number of cups of juice in each pack of apples.

framing in equation form we get;

14x+6y=46 \ \ \ \ equation \ 2

Now Subtracting equation 1 from equation we get;

14x+6y-(8x+6y)=46-34\\\\14x+6y-8x-6y=12\\\\6x=12

Now dividing both side by 6 we get;

\frac{6x}{6}=\frac{12}{6}\\\\x=2\ cups

Now we will substitute the value of 'x' in equation 1 we get;

8x+6y=34\\\\8\times2+6y=34\\\\16+6y=34

Subtracting both side by 16 we get;

16+6y-16=34-16\\\\6y= 18

Now dividing both side by 6 we get;

\frac{6y}{6}=\frac{18}{6}\\\\y=3

Hence Each packet of orange can make 2 cups of juice and each packets of Apple can make 3 cups of juice.

5 0
3 years ago
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
5. Describe the pattern below.<br> 9, 12, 15, 18, 21, 24
Dafna11 [192]

Answer:

The numbers increase by 3

Step-by-step explanation:

The difference between all the numbers in the sequence have a gap of 3

9 and 12 --gap of 3

12 and 15--gap of 3

18 and 21--gap of 3

21 and 24--gap of 3

6 0
3 years ago
Read 2 more answers
Lines k and l are parallel. Lines m and n intersect lines k and l to form 2 triangles. The top triangle has angles 1, 2, 3. The
GaryK [48]

Answer:

It is C, line KL has a slope of 0 and line MN is undefined and they're perpendicular

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
please answer this question fast and please show all your work because I am locking for how can you do it please ​
inysia [295]

Option C is the correct values of the relationship between the number of cakes the baker makes and the number of bags of flour uses.

Solution:

Option A: Ratio of cakes baked to bags of flour used

$\frac{9}{4}, \frac{18}{6}=\frac{3}{1} \text { and } \frac{27}{9}=\frac{3}{1}

Here the ratios are not same.

So, this option is not true.

Option  B: Ratio of cakes baked to bags of flour used

$\frac{6}{2}=\frac{3}{1}, \frac{12}{4}=\frac{3}{1} \text { and } \frac{18}{6}=\frac{3}{1}

Here the ratios are same.

So, this option is true.

Option C: Ratio of cakes baked to bags of flour used

$\frac{4}{9}, \frac{6}{18}=\frac{1}{3} \text { and } \frac{9}{17}

Here the ratios are not same.

So, this option is not true.

Option D: In this table cakes baked is 6 and the bags of flour is 18.

But a baker made 18 cakes using 6 bags of flour.

So, this option is not true.

Hence option C is the correct values of relationship between the number of cakes the baker makes and the number of bags of flour uses.

6 0
3 years ago
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