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disa [49]
3 years ago
14

In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.

If there are 45 students in her class, how many have both a dog and a cat as pets?
Mathematics
2 answers:
harina [27]3 years ago
7 0
I believe 36 have both dogs and cats as pets
Travka [436]3 years ago
5 0

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

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3 years ago
The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re
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Answer:

0.070

Step-by-step explanation:

Y = number on trial

Y has a negative binomial distribution

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8 0
3 years ago
ANSWER FAST ILL GIVE BRAINLIEST!!
Dominik [7]

Given:

A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.

To find:

The surface area of the pyramid to the nearest whole number.

Solution:

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Area of a square is

A_1=(edge)^2

A_1=(10)^2

A_1=100

So, area of square base is 100 sq. in.

Area of a triangle is

A_2=\dfrac{1}{2}\times base\times height

A_2=\dfrac{1}{2}\times 10\times 4

A_2=20

So, area of each triangular surface is 20 sq. in.

Now, the total surface area of the pyramid is

Total area = Area of square base + Area of 4 congruent triangles.

A=A_1+4\times A_2

A=100+4\times 20

A=100+80

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Therefore, the area of the pyramid is 180 sq. in.

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3 years ago
The line passes through the points (-5,6) and (3,-2)<br><br> The equation of the line is
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Answer:

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Step-by-step explanation:

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If this answer is correct, please make me Brainliest!

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