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2 years ago

Evaluate |3 -5 + 7|. 15 o -5 -15 5

Mathematics

1 answer:

Fed [463]2 years ago

7 0

Answer:

Step-by-step explanation:

subtract 3-5=-2

-2+7= 5

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Please answer and put how

muminat

6 + m/4 = 3 (subtract 6 from both sides)
m/4 = -3 (multiply both sides by 4)
m = -12

Can plug in to original equation to check work:
6 - 12/4 = 3
6 - 3 = 3
3 = 3

The answer m = -12 checks out

3 0

2 years ago

Read 2 more answers

What is 3/16 divided by 1/4 fraction form

Ulleksa [173]

The answer to this is,1/4.

3 0

3 years ago

Graph f(x)=4x calculate the initial value of the function

tekilochka [14]

Answer:

Step-by-step explanation: your going to find the y intercept

find the domain

find the inverse

find the derivative

find the extrema

find the horizontal asymptotes

tell weather its even or odd

but its X=0

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2 years ago

8. Write y-x-y-x in simplest form.<br><br><br><br>10 points

alisha [4.7K]

Answer:

Easy -2x

Step-by-step explanation:Because both a positive y and a negative y cancle out eachother so all thats left is both of the negative x's

4 0

2 years ago

22. Determine the value of c so that the line

tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints D(c, -7) and E(5, -3).

Using slope formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$ we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

$\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}$

We have:

$x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \$

Putting values and finding c

$\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2$

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0

3 years ago