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3 years ago

Tom drove 605 miles in 11 hours. How many miles would he drive in 9 hours

2 answers:

5 0

495 miles; Divide 605 by 11 to find how many miles he went per hour, then take the result and multiply it by 9 to find the number of miles he went in that timespan.

605/11 = 55mph

55x9=495 miles

german3 years ago

3 0

I think the answer would be 99

you multiply 9 and 11 and get 99

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Solve each equation. d(d+3)-d(d-4)=9d-16

likoan [24]

Answer:

2d+3d-2d+4d= 9d-16

2d is cancelled

3d+4d=9d-16

7d=9d-16

16=9d-7d

16=2

16/2

d=8

3 0

3 years ago

A scoop of ice cream is the shape of a whole perfect sphere sits in a right cone.

Andrei [34K]

Answer:

10 cm

Step-by-step explanation:

The volume of a sphere is given by the formula ...

V = 4/3πr³

The volume of a cone is given by the formula ...

V = 1/3πr²h

The ratio of the volume of the cone to that of the sphere is ...

Vcone/Vsphere = (1/3πr²h)/(4/3πr³) = h/(4r)

In order for the ratio to have a value of 1, we must have ...

h = 4r

The height of the cone must be 4×2.5 cm = 10 cm to fit all of the ice cream.

7 0

3 years ago

Read 2 more answers

3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall

Katen [24]

Answer:

The volume of the toy is $V=5.23\ ft^3$

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

$V=\frac{2}{3}\pi r^{3}$

In this problem, the wide of the toy is equal to the diameter of the hemisphere

$D=2\ ft$

$r=2/2=1\ ft$ ----> the radius is half the diameter

substitute

$V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3$

step 2

Find the volume of the cone

The volume of the cone is given by

$V=\frac{1}{3}\pi r^{2}h$

we know that

The radius of the cone is the same that the radius of the hemisphere

$r=1\ ft$

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

$h=4-1=3\ ft$

substitute the given values

$V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3$

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

$V=(\frac{2}{3} \pi+\pi)\ ft^3$

$V=(\frac{5}{3}\pi)\ ft^3$

assume

$\pi=3.14$

$V=\frac{5}{3}(3.14)=5.23\ ft^3$

5 0

4 years ago

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

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$\cot(x)+\tan(x)$

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