Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Answer:
- 0.5 - 1.7 = - 2.2
Step-by-step explanation:
We need to add two numbers using the number line.
Steps to Add Numbers on the Number Line:
When we add a negative numbers that we move the point to the left of the number line.
We are adding two negative numbers. Locate the first number which is -0.5. Then, add negative 1.7 to it which means moving the existing point 1.7 units to the left of the number line.
So, we get 2.2 on the left.
2.2 is left side it means sign is negative.
Final answer is -2.2
C. when opposite sides are congruent and parallel
Answer:
I think it would be -2 if it has a negative charge
Step-by-step explanation: