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3 years ago

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Find a recurrence relation for the number of sequences of 1s, 3s, and 5s whose terms sum to n. (b) Repeat part (a) with the adde

d condition that no 5 can be followed by a 1. (c) Repeat part (a) with the condition of no subsequence of 135

1 answer:

Vladimir [108]3 years ago

3 0

Answer:

The solution has been given in the following attachment .

Step-by-step explanation:

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A number b divided by -3 is greater than or equal to 6

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Answer:

$\frac{b}{-3}\geq 6\\\\ b\leq 6.(-3)=-18\\\\ b\leq -18$

Step-by-step explanation:

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Find all real solutions of the equation. <br> x4/3 − 7x2/3 + 10 = 0

BlackZzzverrR [31]

Solve by Factoring x^(2/3)-7x^(1/3)+10=0
x
2
3
−
7
x
1
3
+
10
=
0
x
2
3
-
7
x
1
3
+
10
=
0
Rewrite
x
2
3
x
2
3
as
(
x
1
3
)
2
(
x
1
3
)
2
.
(
x
1
3
)
2
−
7
x
1
3
+
10
=
0
(
x
1
3
)
2
-
7
x
1
3
+
10
=
0
Let
u
=
x
1
3
u
=
x
1
3
. Substitute
u
u
for all occurrences of
x
1
3
x
1
3
.
u
2
−
7
u
+
10
=
0

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Eva8 [605]

Answer:

The measure of angle 1 is 55.

Step-by-step explanation:

The top angle= 75 because of the vertical angle theorem

The right angle= 50 because of the alternate exterior angle theorem

75+50=125

There are 180 degrees in a triangle so the angle has to equal 55

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