84 is what percent of 212%

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

Find the value of z.

nataly862011 [7]

Answer:

z = $\frac{50}{3}$

Step-by-step explanation:

The ratio of corresponding sides are equal, that is

$\frac{z}{10}$ = $\frac{20}{12}$ ( cross- multiply )

12z = 200 ( divide both sides by 12 )

z = $\frac{200}{12}$ = $\frac{50}{3}$

8 0

3 years ago

Why would I rewrite this

Ratling [72]

You are finding 3 1/6 - 1 5/6.

To solve, you should first change it so that the numerator of the first fraction is greater than the numerator of the second. Note that both have the same denominator (6). Subtract as usual:

3 1/6 = 2 7/6

2 7/6 - 1 5/6 = 1 2/6

1 2/6 is your answer.

~

7 0

3 years ago

Write the pair of fractions as a pair of fractions with a common Denominator?

umka21 [38]

Answer:

2) 2/4 1/4

3) 6/8 5/8

4) 4/12 3/12

5) 8/24 15/24

7 0

2 years ago

Read 2 more answers

Solve each equation below for indicated variable<br><br> A) am = n+p, for a

frez [133]

In terms of algebra, writing "am" is the same as writing "a*m" or "a times m"

To undo the multiplication, we use division. We will divide both sides by m to get 'a' all by itself on the left side

So...
am = n+p
a*m = n+p
(a*m)/m = (n+p)/m .... divide both sides by m
a = (n+p)/m ... notice how the 'm's cancel out when we divide on the left side

Final Answer: a = (n+p)/m
You must use parenthesis to indicate that all of "n+p" is over m or you can write it like this $a = \frac{n+p}{m}$

3 0

3 years ago