A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7 
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB = = 
= 5
DE = 
= 
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
If these are the missing choices:
A) Segments ST and PQ are parallel.
B) Angle P is congruent to itself due to the reflexive property.
C) RP is a transversal line passing ST and PQ.
<span>D) Angles RTS and RQP are congruent due to the Corresponding Angles Postulate.
</span>The fact that is not used to prove that PQR is similar to STR is <span>B) Angle P is congruent to itself due to the reflexive property.
</span>
Reflexive property in the given image is on Angle R not angle P.
slope = (y2-y1)/(x2-x1)
m =(-2-7)/(8-0)
m =(-9/8)
slope is -9/8
the y intercept is 7 (0,7)
y = mx +b
y = -9/8 x+7
Answer: y = -9/8x +7
Answer:
3.67+(-0.43)+(-0.44)
3.67-0.43-0.44
3.24-0.44
<em><u>2.8 </u></em><em><u>Ans</u></em>
Set up a proportion with the similar sides. Then you should find what KB is. Sorry I couldnt answer directly. Im actually doing math right now
