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sergejj [24]
4 years ago
14

if the equation of our line is y=2x-3, and our ordered pair is (0,-3) please put the coordinates in the equation

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
3 0

Answer:(6,-3)

Step-by-step explanation:

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Graph the solution if the this inequality 4/9x-10>x/3-12
cupoosta [38]

You want to isolate the x-term from the constant term, so you can subtract x/3 and add 10. This gives you

... 4/9x -10 -x/3 +10 > x/3 -12 -x/3 +10

... 1/9x > -2 . . . . . . collect terms

Now, you can multiply by 9 to see the condition on x.

... 9(1/9x) > -2(9)

... x > -18


On the x-y plane, the graph of this will be a dashed line at x=-18, and the half-plane to the right of that line will be shaded.


On a number line, there will be an open circle at x=-18, and the number line to the right of that circle will be marked (bold, colored, shaded, whatever).

4 0
3 years ago
2(4x-1)+3=7<br> i'm little confused on this
Ratling [72]

Answer:

x = \frac{3}{4}

Step-by-step explanation:

Since you cannot subtract -1 from 4x, you multiply 2 × 4x = 8x

Now, you have 8x - 1 + 3 = 7

Seperate the 8x from the other numbers

8x = 1 - 3 + 7 ---> 6

8x = 6

Now simplify

x = \frac{6}{8}  <----- to reduce, divide the numerator and denominator by 2

Hence,

x =  \frac{3}{4}

4 0
3 years ago
A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
the height of a cylinder is three times the diameter of the base . The surface area of thre ylinder is 126pi ft^2. What is thr r
Over [174]
The answer is 3 ft

The surface area (SA) of a cylinder with radius r and height h is:
SA = 2πr² + 2πrh = π(2r² + 2rh)

We have:
SA = 126π ft²
h = 3 * d
d = 2r
h = 3 * 2r = 6r

126π = π(2r² + 2rh)
126 = 2r² + 2rh
126 = 2r² + 2r * 6r
126 = 2r² + 12r²
126 = 14r²
r² = 126/14
r² = 9
r = √9
r = 3
8 0
3 years ago
Read 2 more answers
What is .181818... as a fraction?
LekaFEV [45]
181818/1000000. let me know if im wrong! <3
4 0
3 years ago
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