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2 years ago

In the diagram, AITP - ANGO. Find the values of x and y. y = X=

Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer:

x = 25, y = 9

Step-by-step explanation:

Since the triangles are congruent then corresponding angles and sides are congruent, thus

∠ O = ∠ P , substitute values

6y - 14 = 40 ( add 14 to both sides )

6y = 54 ( divide both sides by 6 )

y = 9

and

NG = IT , that is

x - 2y = 7 ( substitute y = 9 into the equation )

x - 2(9) = 7

x - 18 = 7 ( add 18 to both sides )

x = 25

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The following lines are ______ <br><br> 4x + 2y = 10 y = -2x + 15

zmey [24]

Answer:

Parallel

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

4x + 2y = 10 ( subtract 4x from both sides )

2y = - 4x + 10 ( divide through by 2 )

y = - 2x + 5 ← in slope- intercept form

with slope m = - 2

and

y = - 2x + 15 ← is in slope- intercept form

with slope m = - 2

• parallel lines have equal slopes

then the 2 lines are parallel

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1 year ago

Read 2 more answers

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Elenna [48]

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2 years ago

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

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