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Alex
3 years ago
12

What is a irregular concave polygon

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

An irregular polygon is any polygon that is not a regular polygon. It can have sides of any length and each interior angle can be any measure. They can be convex or concave, but all concave polygons are irregular since the interior angles cannot all be the same.

Step-by-step explanation:

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LA and B are vertical angles. If m_A = (5x + 5) and m_B = (4x + 29), then find the measure of_A.​
OverLord2011 [107]

Answer:

If A and B are vertical angles, then they are congruent, so their measures are equal.

This means

(5x + 5)º = (4x + 29)º

5x + 5 = 4x + 29

x = 24

Then angle A has measure (5*24 + 5)º = 125º.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Read 2 more answers
Help please thank you!
monitta

Answer:

• multiplied by 4p: (x -h)² +4pk = 0

• zeros for k > 0: none

• zeros for k = 0: one

• zeros for k < 0: two

Step-by-step explanation:

a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...

(x -h)² +4pk = 0

__

b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)

__

c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)

__

d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.

_____

The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.

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3 years ago
How do you multiply fractions
dexar [7]
This really depends on the fraction; if there are variables in the equation, if they are full numbers,etc. I'd really recommend looking up khan academy on YouTube and that will really help you out!
4 0
3 years ago
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