Picture 1 shows the reflection of ABC 180° clockwise about the origin. To draw A'B'C' we draw the line segments AO, BO, and CO and extend them such that O is the midpoint of line segments AA', BB', and CC' respectively.
Picture 2 shows the line y=-x (the yellow line.) This is the line containing all points of the form (x, -x), that is, this points contains (1, -1), (-2, 2) etc...
We see that point C' is already on this line, and we draw the reflections of points B and C with respect to this line, to find B'' and C'' with coordinates as shown in the figure.
The answer is 2/6 which would reduce to 1/3 because he could only roll a 5 or higher so he could only roll a 5 or a 6 which is 2 numbers out of 6. Which makes it 2/6 and 2/6 reduces to 1/3 !
An equation is an expression of exponential growth if the base of the exponential term is more than 1 and it is an exponential decay if the base number is less than 1.
A. <span>H=5.9 (0.82)^t Base number: 0.82 --> exponential decay
B. y=0.8 (3.6)^t Base number = 3.6 --> exponential growth
C. f(t)=0.72 (15)^t Base number = 15 --> exponential growth
D. A=4/9 (8)^t Base number = 8 --> exponential growth
E. A= (4/3)^t Base number = 4/3 --> exponential growth
F. H= 7/2 (5/6)^t Base number = 5/6 ---> exponential decay
G. g(x)= 0.3(x) Base number = 1 --> Neither</span>