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4 years ago

What is X^2 -8x+9=0 written in the form(x-P)^2 =q?

Mathematics

1 answer:

Olenka [21]4 years ago

8 0

$x^{2} -8x+9=0$
$x^{2} -8x=-9$
$x^{2} -8x+16=-9+16$
$(x-4)^{2}=7$

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You make $10 on the first day, $20 on the second day, $40 on the third day, $80 on the fourth day, and so on. What is your total

Trava [24]

The answer to this question is 5,120 you have to multiply by 2

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3 years ago

The sum of two numbers is 64. The difference between the numbers is 14. Write a system

Anastasy [175]

Answer:

They say that the sum of the two numbers (x and y) is 64, so we can write our first equation by adding them and setting that sum equal to 64:

x + y = 64

The question also tells us that their difference is 14. Similarly to before, we'll just subtract the two numbers and set that difference equal to 14:

x - y = 14

Now from here, you know how to continue with substitution to find the values for x and y. Just remember when you get a word problem to break it down and look for key words like sum, difference, or product, and from there you'll be able to build your system of equations.

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2 years ago

Put these numbers in order from least to greatest. 8.1 9.81 0.891 0.01

iogann1982 [59]

0.01, 0.891, 8.1, 9.81

5 0

3 years ago

Read 2 more answers

Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.

dedylja [7]

g(x) is basically transformed f(x). First, let's focus on f(x) graph. Notice how the graph has slope of 1 and intersect y-axis at (0,0).

Which means that our equation for f(x) is:

$\large{f(x) = x}$

Now then we focus on g(x). g(x) is f(x+k). That means if f(x) = x then f(x+k) would mean substitute x = x+k in the equation.

$\large{f(x + k) = x + k }\\ \large{g(x) = x + k}$

Next, we want to find the value of k. In the slope-intercept form or y = mx+b where m = slope and b = y-intercept. Notice the g(x) graph and see that the graph intersects y-axis at (0,4). Therefore k = y-intercept = 4.

$\large{g(x) = x + 4}$

Answer

g(x) = x+4
Therefore the value of k is 4.

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3 years ago

Find the integral of 3/sqrt of 1-4x^2

erastovalidia [21]

$\int {\frac{3}{\sqrt{1-4x^{2}}}} \, dx$
$= 3\int {\frac{1}{\sqrt{1-4x^{2}}}} \, dx$
$= 3\int {\frac{1}{\sqrt{4(\frac{1}{4} - x^{2})}}} \, dx$
$= \frac{3}{2}\int {\frac{1}{\sqrt{\frac{1}{4} - x^{2}}}}\, dx$

$= \frac{3}{2}sin^{-1}(2x) + C$

8 0

3 years ago