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asambeis [7]
3 years ago
5

The volume V of a solid right circular cylinder is given by V = πr2h where r is the radius of the cylinder and h is its height.

A soda can has inner radius r = 1.5 inches, height h = 6 inches, wall thickness 0.04 inches, and top and bottom thickness 0.07 inches. Use linearization to compute the volume, in cubic inches, of metal in the walls and top and bottom of the can. Give your answer to 2 decimal places.
Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

8.20in³

Step-by-step explanation:

Given V = πr²h

r is the radius = 1.5in

h is the height = 6in

thickness of wall of the cylinder dr = 0.04in

top and bottom thickness dh 0.07in+0.07in = 0.14in

To compute the volume, we will find the value of dV

dV = dV/dr • dr + dV/dh • dh

dV/dr = 2πrh

dV/dh = πr²

dV = 2πrh dr + πr² dh

Substituting the values into the formula

dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14

dV = 2π (0.36)+π(1.89)

dV = 0.72π+1.89π

dV = 2.61π

dV = 2.61(3.14)

dV = 8.1954in³

Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)

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topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

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pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
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The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
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Since the length of the normal vector does not change the direction, we simplify the normal vector as
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We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
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expand and simplify, we get the equation
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Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

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Answer:

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