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ludmilkaskok [199]
3 years ago
5

16^1/4 = a. 1/2 b. 2 c. 4

Mathematics
2 answers:
stiv31 [10]3 years ago
4 0

Answer:

c

Step-by-step explanation:

baherus [9]3 years ago
3 0
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ If you have a fraction as a power, you have to 'root' it by whatever the denominator is

In this case it is 4, so we do this:

\sqrt[4]{16} = 2

Therefore, the answer is B. 2

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

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A student researcher compares the heights of men and women from the student body of a certain college in order to estimate the d
maria [59]

Answer:

(0.6613, 8.3387)

Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have n_{1} = 15, \bar{x}_{1} = 69.4, s_{1} = 3.09 and

n_{2} = 7, \bar{x}_{2} = 64.9, s_{2} = 2.58. The pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

5 0
3 years ago
If 11,000 is 85% of what was in my bank account, how much did I originally have?
Mrrafil [7]
You can set it up like a proportion:

\frac{11000}{0.85}    \frac{x}{1.00}

Cross multiply: 
11000*1 = 11000
11000/0.85 = 12,941.18

You had roughly $12,941.18 in your bank account.
6 0
3 years ago
Add. (2n+4)+(4a+2) (2n+4)+(4a+2)
IceJOKER [234]

Answer: 8an + 20a + 6n + 14

Step-by-step explanation:

3 0
3 years ago
What is the domain and range for {(0,-5),(1,3),(2,2),(0,4)(-5,6),(3,4)}
Inga [223]
The domain are the x values and the range are the y values.
Domain {0, 1, 2, -5, 3}
Range {-5, 3, 2, 4, 6}

Note: you do not repeat a number if it is already in the domain or range.
7 0
3 years ago
6[5 x (41 - 36) - (8 + 14)]
Otrada [13]

Answer:

i want to say good bye my friend

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3 years ago
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