Step 1: convert the equation into fhe vertex form
To do you can complete squares:
y = - [x^2 + 4x + 3]
y = - [ (x + 2)^2 - 4 + 3]
y = - [ (x + 2)^2 - 1] = - (x+2)^2 + 1
Then the vertex is (-2, 1)
Now you can drasw the vertex
Step 2: Find the roots (zeros)
y = - [ (x + 2)^2 - 1] = 0
(x + 2)^2 - 1 = 0
(x+2)^2 = 1
(x+2) = (+/-) √1
x + 2 = (+/-1)
x = - 2 +/- 1
x = -1 and x = -3
Now you draw the points (-1,0) , (-3,0)
Step 3: find the interception with the y-axis.
That is y value when x = 0
y = - (0)^2 - 4(0) - 3 = -3
Then draw the point (0, -3)
Step 4: given that the coefficent of x is negative (-1) the parabola is open downward.
So, with those four points: vertex (-2,1), (-1,0), (-3,0) and (0,-3), you can sketch the function.
Answer: Simple, this is on E d g e n u t y, the answer is O, I think.
What is the question though in A #1
Answer:
A.
Step-by-step explanation:
multiply the to equation by 6, multiply the bottom equation by -5 (you will get +30y and -30y to eliminate each other)then add equations (you will have +48x and +45x which will be = -42 + 20)
Answer:
The answer should be C
Step-by-step explanation:
