is there a value to y? if not, this is what I got:
Y^2 + 2y + 3
just plug into a calculator
(8z - 10) ÷ (-2) + 5(z - 1) = 8z - 10 ÷ -2 + 5z - 5 = 8z + 5 + 5z - 5 = 13z
Answer:
The Depth of the lake had increased by 19%.
Step-by-step explanation:
Given:
Depth of lake few months ago = 1300 ft
depth of lake currently = 1547 ft
We need to find the percent of increase in depth of lake.
Solution:
First we will find the increase in depth of lake.
Increase in depth of lake can be calculated by subtracting Depth of lake few months ago from depth of lake currently.
framing in equation form we get;
increase in depth of lake =
Now to find the percent of increase in depth of lake we will divide increase in depth of lake from Depth of lake few months ago and then multiply by 100.
framing in equation form we get;
percent of increase in depth of lake =
Hence the Depth of the lake had increased by 19%.