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3 years ago

A bus driver drives 547.25 miles on day 1 of a trip. On day 2, he drives 327.875 miles.

Mathematics

2 answers:

liq [111]3 years ago

8 0

219.375 because 547.25 minus 327.875 is 219.375.

Hoochie [10]3 years ago

3 0

I am not sure I am correct but maybe if you divided it will be 1.66 or if you subtract it´s 219.375 but sorry

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Scott is four more than double the age of Todd. Scott is 56. What is Todd's age?

SSSSS [86.1K]

Answer: 26 years old

Step-by-step explanation:

Since Scott is four more than double the age of Todd, start by taking away four from Scott's age.

56-4=52

Then take half of that because that would be double of Todd's age

52/2=26

Todd is 26 years old.

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2 years ago

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solmaris [256]

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3 years ago

6 people go eat some order chicken dinner for $14 and some order steak dinner for $17. If the total bill was $99, how many peopl

White raven [17]

Answer:

5 people bought the $17 steak and 1 person bought the $14 chicken.

Step-by-step explanation:

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2 years ago

Find the value of x. Round to the nearest tenth

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70.5

Step-by-step explanation:

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3 years ago

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

2 years ago