A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
C
Step-by-step explanation:
f"(x) < 0, which means the function is concave down at all values of x.
For any such function, within the domain of a ≤ x ≤ b, the secant line S(x) is below the curve of f(x), and the tangent line T(x) is above the curve of f(x).
Here's an example:
desmos.com/calculator/fyektbi9yl
Answer:
2 yay
Step-by-step explanation:
1. The graph is a parabola.
2. The parabola opens up, because there's no negative number in front of 
.
3. The vertext is (5,-1), because of the vertex form.
This means that that -1 will be the least y-value used on the graph and the garph will open up from there.
The range is (-1, infinity) or { y | y > -1 }.
