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Sav [38]
3 years ago
5

To see why, calculate the energy absorbed from your body if you eat 0.70 kg of -9 ∘c snow which your body warms to body temperat

ure of 37∘c.
Biology
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

The energy absorbed from the body = 302.82 J

Explanation:

Note: a Snow is an an ice

The heat absorbed from the body = heat required to change the temperature of  snow from -9 °C to 37 °C. + The latent heat of snow

H = c₁m(t₂-t₁) + c₂m ........................... Equation 2

Where H = heat absorbed from the body, c₁ = specific heat capacity of ice, c₂ = specific latent heat of fusion of ice,  m = mass of ice.

<em>Given: m = 0.7 kg, t₂ = 37 °C, t₁ = -9 °C</em>

<em>Constant: c₁ = 2.1 g/g.°C, c₂ = 336 J/g</em>

<em>Substituting these values into equation 1,</em>

<em>H = 0.7×2.1×(37+9) + 0.7(336)</em>

<em>H = 67.62 + 235.2</em>

H = 302.82 J

<em>Thus, the energy absorbed from the body = 302.82 J</em>

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