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Masja [62]
3 years ago
11

Rey has 4 bags of pecans. Each bag is 3/5 pounds. How many pounds of pecans does Rey have?​

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

12/5 lbs or 2.40 lbs

Step-by-step explanation:

3/5 multiplied by 4 is 12/5.

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The ratio of two numbers is 7 to 5. The sum of the numbers is 24. What are the numbers?
Kipish [7]

Answer:

14 and 10

Step-by-step explanation:

The ratio of the 2 numbers = 7x : 5x

The sum of the 2 numbers is 24, hence

7x + 5x = 24

12x = 24 ( divide both sides by 12 )

x = 2

7x = 7 × 2 = 14

5x = 5 × 2 = 10

Thus the numbers are 14 and 10

5 0
3 years ago
How many solutions does the equation 6y − 3y − 7 = −2 + 3 have?
Ludmilka [50]
The only solution to this equation is 8/3, therefore the answer is C.
4 0
3 years ago
Please help is urgent
vazorg [7]

Answer:

x ≈ 7.2

Step-by-step explanation:

Given a tangent- secant from an external point to the circle, then

the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )

x = \sqrt{52} ≈ 7.2 ( to the nearest tenth )

5 0
3 years ago
Twenty different books are to be put on five book shelves, each of which holds at least twenty books.
olya-2409 [2.1K]

Answer:

(a) 10,626 different arrangements

(b) 95,367,431,640,625 different arrangements

(c) 2.5852017 × 10²² different arrangements

Step-by-step explanation:

(a) How many different arrangements are there if you only care about the number of books on the shelves (and not which book is where)?

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626 arrangements

(b) How many different arrangements are there if you care about which books are where, but the order of the books on the shelves doesn't matter?

Since the order of the books on the shelves does not matter,

The calculation is given as

5²⁰ = 95,367,431,640,625 arrangements

(c) How many different arrangements are there if the order on the shelves does matter?

Since order matters now

Step 1

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626

Step 2

We find the factorial of the number books

= 20!

= 2,432,902,008,176,640,000

Step 3

The different arrangements there are if the order on the shelves does matter is calculated

= 10,626 × 2,432,902,008,176,640,000

= 2.5852017 × 10²² different arrangements

8 0
3 years ago
Can someone help me in 5 and 7 please
pav-90 [236]

5

Write -22 in the middle of the graph, number the rest of the graph accordingly and draw an open circle around the line under the -22 and draw a line along the graph to the right


7

Write 15 in the middle of the graph and number the rest of the graph accordingly, draw a colored in circle under the 15 on the graph and draw a line to the to the right


Sorry, I'm on the road and couldn't take a picture of the solution


4 0
3 years ago
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