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3 years ago

Can you please explain how to do the above completing the ratio tables. Thank you in advance for your help

Mathematics

1 answer:

Stells [14]3 years ago

7 0

Ratio tables show equivalent ratios between two quantities. You can create a ratio table by multiplying (or dividing) both quantities in the ratio by the same value to find an equivalent ratio.

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Question 7 A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

QveST [7]

Answer:

1) $S=\{1,2,3,4,5,6\}$

2) $O=\{1,3,5\}$

Step-by-step explanation:

Given : A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

To find : Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling an odd number. If there is more than one element in the set, separate them with commas ?

Solution :

A number cube with faces labeled from 1 to 6 will be rolled once.

The sample space describing all possible outcomes is given by

$S=\{1,2,3,4,5,6\}$

All of the outcomes for the event of rolling an odd number is given by

$O=\{1,3,5\}$

6 0

3 years ago

9+8{7•6-5[4+(3-2•1)]}=?

34kurt

Answer:

145

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

9+8{7*6-5[4+(3-2*1)}]}

9+8{7*6-5[4+1]}

9+8{7*6-25}

9+8{42-25}

9+136

145

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

5 0

3 years ago

Which figure has two pairs of congruent sides and more than two lines of symmetry?

Advocard [28]

C. trapezoid

a trapezoid's legs are congruent, while the bases are symmetrical

a square is the answer you would want, because it is always true, while a trapezoid is only "sometimes" true

thanks Kaikers :D

5 0

4 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that

Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0

3 years ago