Sampling errorThe natural discrepancy, or amount of error, between a sample statistic and its corresponding population parameter.distribution of sample means<span>The collection of sample means for all of the possible random samples of a particular size (n) that can be obtained from a population.</span>sampling distributionA distribution of statistics obtained by selecting all of the possible samples of a specific size from a population.central limit theorem<span>For any population with mean μ and standard deviation σ, the distribution of sample means for sample size n will have a mean of μ and a standard deviation of σ/√n and will approach a normal distribution as n approaches infinity.</span><span>expected value of M</span>The mean of the distribution of sample means is equal to the mean of the population of scores, μ, and is called this.<span>standard error of M</span><span>The standard deviation for the distribution of sample means. Identified by the symbol σ˯M. This standard error provides a measure of how much distance is expected on average between a sample mean (M) and the population mean (μ).</span>law of large numbers<span>States that the larger the sample size (n), the more probable it is that the sample mean is close to the population mean.</span>
<span>Let's find out the ball's acceleration
V^2 = U^2 + 2as
Where the distance S = 6 feet and U = 45.
Suppose he just took off so V = 0 and we are left with U^2 =2as
(45)^2 = 2a(6)
a = 2025/12 = 168.75 ft/s^2
Also S = ut + 1/2 at^2
Here S = 5ft and U= 0; a = 168.75. So we have 5 = (1/2) * 168.75 * t^2
So we have 5 * 2 = 168.75 t^2
T^2 = âš 10/ 168.75 = 0.00596 = âš0.006
T = 0.0077s</span>
Answer:
y less than or equal to 2x+1
Step-by-step explanation:
Move the slope to the other side and cancel the 4 on the y to get only y. Whatever you do on one side you must do on the other.
