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Klio2033 [76]
3 years ago
13

Bags of sugar from a production line have a mean weight of 5.020 kg with a standard deviation of 0.078 kg. The bags of sugar are

packed in cartons of 20 bags each, and the cartons are piled in lots of 12 onto pallets for shipping. a) What percentage of cartons would be expected to contain less than 100 kg of sugar? b) Find the upper quartile of sugar content of a carton. c) What mean weight of an individual bag of sugar will result in 95% of the pallets weighing more than 1200 kg.?

Mathematics
1 answer:
Sindrei [870]3 years ago
4 0

Answer:

a.0.126

b.100.6356

c.5.010

Step-by-step explanation:

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If h(x)=1-2/3x, find h(-6).
Alex

Answer:

  5

Step-by-step explanation:

Put -6 where x is and do the arithmetic.

  h(x)=1-\dfrac{2}{3}x\\\\h(-6)=1-\dfrac{2}{3}(-6)=1-\dfrac{-12}{3}=1-(-4)=1+4\\\\\boxed{h(-6)=5}

3 0
3 years ago
Summarize the rules for multiplying powers with the same base dividing powers with the same base raising a product to a power an
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3 years ago
By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i < ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

3 0
3 years ago
Sergio works at a bakery and needs to cover
Elan Coil [88]

Answer:

The surface area that Sergio needs to frost on each cake is 3,238 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the cylindrical cake is equal to the lateral area plus the area of the top of cylinder (remember that the bottom of the cake does not need frosting)

so

SA=\pi r^{2}+2\pi r h

we have

r=40.2/2=20.1\ cm ---> the radius is half the diameter

h=15.6\ cm

\pi=3.14

substitute the given values

SA=(3.14)(20.1)^{2}+2(3.14)(20.1)(15.6)

SA=1,268.59+1,969.16\\SA=3,237.75\ cm^2

Round up to the  nearest whole number

SA=3,238\ cm^2

therefore

The surface area that Sergio needs to frost on each cake is 3,238 square centimeters

5 0
3 years ago
1. Is 5(x+1) the same as 5x+1? Explain your
tatiyna

Answer:

Step-by-step explanation:

5(x+1), when expanded, becomes 5x + 5, which is ot the same as 5x + 1.

5 0
3 years ago
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