Adult ticket (a) = $5
Child ticket (c) = $2
785 tickets = $3280
a + c = 785 tickets
5a + 2c = $3280
c = 215 child tickets
a = 570 adult tickets
570 + 215 = 785 tickets
5(570) + 2(215) = $3280
There were 215 child tickets sold on Saturday
Answer:
0.153
Step-by-step explanation:
We have been given that Mafalda has a save percentage of 0.738 so far this hockey season. Last season, her save percentage was 0.585.
To find improvement in Mafalda's save percentage we will subtract last season's save percentage from this season's save percentage.

Therefore, Mafalda's save percentage improved by 0.153.
Answer:
try resedning the picture it wont open/load
Step-by-step explanation:
Answer:
Randomly selected adult has an IQ less than 136 is 0.9641
Step-by-step explanation:
It is given that, it is normal distribution with mean 100 and SD as 20.
So, let's use the formula of z-score
z=
For this problem,
x= 136
Plug in this value into the formula
z-score=
=1.8
Now, use z-score table to find the probability
Find the corresponding value for the row 1.8 and the column 0.00, we do get 0.9641
So, Randomly selected adult has an IQ less than 136 is 0.9641
Answer: she will have $2042.4 have in the account after 1 year.
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $2000
r = 2.1% = 2.1/100 = 0.021
n = 12 because it was compounded 12 times in a year.
t = 1 year
Therefore,
A = 2000(1 + 0.021/12)^12 × 1
A = 2000(1 + 0.00175)^12
A = 2000(1.00175)^12
A = $2042.4