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Katena32 [7]
3 years ago
12

Simplify the following expression

Mathematics
1 answer:
garri49 [273]3 years ago
3 0
The answer is B.
Since the fractions are the same (5 )you leave it as it is so you just multiply the powers and then add the power
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the value of an investment decreased by 10%. The original amount of the investment was $75 what is the current value of the inve
pishuonlain [190]

Answer:

67.5

Step-by-step explanation:

6 0
2 years ago
5. &amp; 7. simplify <br> 9. &amp; 11. factor completely
snow_tiger [21]
5)

= - i - 2 - 3i
= - 4i - 2
= - 2 (2i + 1)

7)

= - 4 [(2 -2i - i (8 - 4i)]
= - 4 (2 - 2i - 8i + 4i^2)
= - 4 (4i^2 - 10i + 2)
= (- 4) (2) (2i^2 - 5i + 1)
= - 8 (2i^2 - 5i + 1)

9)

= p^2 - 4p - 4p + 16
= p (p - 4) - 4 (p - 4)
= (p - 4) (p - 4)
= (p - 4) ^2

11)

= p^2 - 8p - 8p + 64
= b (b - 8) - 8 (b - 8)
= (b - 8) (b - 8)
= (b - 8)^2
5 0
3 years ago
In ΔABC (m∠C = 90°), the points D and E are the points where the angle bisectors of ∠A and ∠B intersect respectively sides BC an
Airida [17]

This is a little long, but it gets you there.

  1. ΔEBH ≅ ΔEBC . . . . HA theorem
  2. EH ≅ EC . . . . . . . . . CPCTC
  3. ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
  4. ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
  5. ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
  6. ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
  7. ΔDAC ≅ ΔDAG . . . HA theorem
  8. DC ≅ DG . . . . . . . . . CPCTC
  9. ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
  10. ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
  11. ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
  12. ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
  13. (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
  14. ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
  15. This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
5 0
3 years ago
For the following exercise, determine the range (possible values) of the random variable, X. A batch of 300 machined parts conta
solmaris [256]

Answer:

{0,1,2,3,4,5}

Step-by-step explanation:

We are given that

Total number of  machine parts=300

Number of defective machine parts=10

Total number of good machine parts=300-10=290

Sample contain parts that do not conform to customer requirement=5

X  is a random variable which is the number of parts in a sample of 5 parts that do not conform to customer requirements.

We have to find the correct answer.

The sample contain 5 parts

Therefore, the possible values of random variable X

0,1,2,3,4,5

Hence, the range of X is given by

{0,1,2,3,4,5}

5 0
3 years ago
HELP what is the coefficient of 14x?<br><br> multiplication<br> 14<br> 14x<br> x
cluponka [151]

Coefficient of 14x is 14

Coefficientis the number in front of the letter. For example, coeffient of 2b is 2. When there is no number in front of the letter the coefficient is 1.

3 0
3 years ago
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