The formula for aerobic respiration in animals can be shown by the equation below. A glucose molecule is broken down by enzymes in the presence of oxygen to make carbon dioxide, water, and ATPs. Carbon IV oxide is expelled by the lungs.
C₆H₁₂O₆ + 6O₂ --> 6CO₂ + 6H₂O + 38 ATP
This process occurs in two stages. Glycolysis (that does not require oxygen) occurs in the cytoplasm of cells. The products of the glucose breakdown in this stage is pyruvate, CO₂ and 2 net ATPs. The pyruvate is then converted to acetyl-CoA that enters the second stage called Citric/Krebs cycle. This second stage happens in the mitochondria. The products are CO₂, H₂O and 34 ATPs
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The answer is Complement
this is for my Gradpoint fellas
Answer:
Peroxidase activity increases and then decreases.
Explanation:
Peroxidase activity is greatly affected by the pH factor. Peroxidase works best at the pH of 7 while decrease or increase in pH will adversely affected its activity. So when change occurs from a moderately acidic environment having pH near 6 to a basic environment, the peroxidase activity increases when reach to neutral but decreases when go further to basic environment so we can say that peroxidase activity greatly affected on the pH of the solution.
The answer is palpitation.
