Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
Answer:
125 meters
Step-by-step explanation:
Let distance = d and time is t
Using the variation;
d = k t^2
So let’s us get k
80 = k * 4*2
16k = 80
k = 80/16 = 5
So for 5 seconds, the distance would be;
d = 5 * 5^2
d = 125 meters
Answer:
The value of y would be 45.5
Step-by-step explanation:
To solve this problem, start with the base form of direct variation.
y = kx
Now we can use our original values to model the equation and find k.
35 = k(2.5)
14 = k
Now we can model the equation as:
y = 14x
Now to find y, when x = 3.25, simply put 3.25 into the equation.
y = 14(3.25)
y = 45.5
When given the scale factor and the factored size of the object, to find the original size, divide the factored size by the scale factor:
0.8 / 3.1 = 0.258 inches
