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Arte-miy333 [17]

2 years ago

12

A spinner with 10 equally sized slices has 10 yellow slices. The dial is spun and stops on a slice at random. What is the probab

ility that the dial stops on a yellow slice?
Write your answer as a fraction in simplest form.

1 answer:

djverab [1.8K]2 years ago

5 0

Answer:

1/10

Step-by-step explanation:

there are 10 slices, so if the probability of it landing on one of them is 1/10

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What is the quotient when the sum of 1,2 and 3 is divided by the product of 1,2 and 3

nexus9112 [7]

Answer: 1

<u>Explanation:</u>

sum = add

quotient = divide

product = multiply

$\frac{1+2+3}{1*2*3} = \frac{6}{6}$ = 1

5 0

3 years ago

Read 2 more answers

A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran

Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

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3 years ago

Someone please help! I’m very confused on this problem.

weqwewe [10]

If i'm mistaken; he needs to buy 3 sheets?

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3 years ago

On a coordinate plane, 2 straight lines are shown. The first solid line has a positive slope and goes through (0, negative 2) an

ExtremeBDS [4]

Answer:

$y\geq x-2$

$x+2y$

Step-by-step explanation:

step 1

<em>Find the equation of the first inequality</em>

Find the equation of the first solid line

we have the ordered pairs

(0,-2) and (2,0)

<u><em>Find the slope</em></u>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{0+2}{2-0}$

$m=\frac{2}{2}$

$m=1$

The equation in slope intercept form is equal to

$y=mx+b$

we have

$m=1$

$b=-2$ ---> the y-intercept is given

substitute

$y=x-2$

Remember that

Everything to the left of the solid line is shaded

so

The inequality is

$y\geq x-2$

step 2

<em>Find the equation of the second inequality</em>

Find the equation of the second dashed line

we have the ordered pairs

(0,2) and (4,0)

<u><em>Find the slope</em></u>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{0-2}{4-0}$

$m=\frac{-2}{4}$

$m=-\frac{1}{2}$

The equation in slope intercept form is equal to

$y=mx+b$

we have

$m=-\frac{1}{2}$

$b=2$ ---> the y-intercept is given

substitute

$y=-\frac{1}{2}x+2$

Remember that

Everything below and to the left of the line is shaded

so

The inequality is

$y$

Rewrite

Multiply by 2 both sides

$2y$

$x+2y$

therefore

The system of inequalities is

$y\geq x-2$

$x+2y$

see the attached figure to better understand the problem

5 0

3 years ago

Read 2 more answers

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

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3 years ago