1. -5^3-4^3
2. -15-64
3. -79
Answer:
The pairs of integer having two real solution for
are




Step-by-step explanation:
Given

Now we will solve the equation by putting all the 6 pairs so we get the following
for 
for 
for 
for 
for 
for 
The above all are Quadratic equations inn general form 
where we have a,b and c constant values
So for a real Solution we must have

for
we have
which is less than 0 ∴ not a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is equal to 0 ∴ a real solution.
for
we have
which is less than 0 ∴ not a real solution.
Answer:
900π m2
Step-by-step explanation:
surface are of a sphere is 4π(r)^2
now diameter is 30m,so radius will be 15 m
how, 4π(15)^2=900π (m2)
Since it is at least 3 means that the club must bring 3 or more ideas so x>=3 which is choice d