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Ivahew [28]
3 years ago
12

-17/40 as a decimal show how pls

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

-0.425

Step-by-step explanation:

-0.425

Brrunno [24]3 years ago
5 0

nevermind sorry I got it wrong

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Turn 1 1/5 to improper fraction
Alex17521 [72]

Answer:

<h2><em><u>6/5</u></em></h2><h2></h2>

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>
4 0
3 years ago
To the nearest tenth, which is the BEST estimate for the volume of the given pyramid?
mixer [17]

Answer:

4.2 cubic inches

Step-by-step explanation:

Find the diagram attached

Volume of the rectangular pyramid = BH/3

B is the base area

H is the height of the pyramid

Given

Base area = 3.2in * 1.4in

Base area = 4.48sq. in

Height = 2.8in

Volume of the rectangular pyramid = 4.48*2.8/3

Volume of the rectangular pyramid = 12.544/3

Volume of the rectangular pyramid = 4.2 cubic inches

5 0
2 years ago
I need help with this
snow_lady [41]

Answer:

x = 2 square roots of 2

Step-by-step explanation:

it is a 45-45-90 triangle and in that the two legs are equal to each other so both are 2 and then the hypotenuse is x times the square root of 2

8 0
2 years ago
Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




8 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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