Answer:
<h2><em><u>
6/5</u></em></h2><h2>
</h2>
Explanation:
Step 1
Multiply the denominator by the whole number
5 × 1 = 5
Step 2
Add the answer from Step 1 to the numerator
5 + 1 = 6
Step 3
Write answer from Step 2 over the denominator
<h2><u>
6/5</u></h2><h2><u>
</u></h2><h2><u>
I hope this answer helps you out! Brainliest would be appreciated.</u></h2>
Answer:
4.2 cubic inches
Step-by-step explanation:
Find the diagram attached
Volume of the rectangular pyramid = BH/3
B is the base area
H is the height of the pyramid
Given
Base area = 3.2in * 1.4in
Base area = 4.48sq. in
Height = 2.8in
Volume of the rectangular pyramid = 4.48*2.8/3
Volume of the rectangular pyramid = 12.544/3
Volume of the rectangular pyramid = 4.2 cubic inches
Answer:
x = 2 square roots of 2
Step-by-step explanation:
it is a 45-45-90 triangle and in that the two legs are equal to each other so both are 2 and then the hypotenuse is x times the square root of 2
Answer:
(1) Area of second triangle= 50 cm^2.
(2) Area of ΔABC=98 cm^2.
and Area of ΔDFG=175 cm^2.
Step-by-step explanation:
<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>
i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

(1)
for the first question:
we have a=2, b=5.
A=8 cm^2.
Hence,

B=50 cm^2.
Hence, the area of second triangle is 50 cm^2.
(2)
In second option we have:
a=6 and b=5.
A-B=77 cm^2.
A=77+B

Hence area of second triangle i.e. ΔDFG is 175 cm^2.
and area of first triangle i.e. ΔABC=175-77=98 cm^2.
Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2