Line segment ST has endpoints (3,2) and (7,4). What is the equation for the perpendicular bisecotr?

1 answer:

7 0

We need Vector ST which is just T - S

(7-3.4-2) = (4,2)

So now we need the perpindicular. The easiest way to do this, is to know that , in R2 that the perindicular is just the negatice inverse. So its (2,-4)

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