The solution to the linear expressions are:
- a. $36.26
- b. -$19.35
- c. $70.38
<h3>Solving linear expressions:</h3>
The solution to linear expression is determined by taking into consideration the arithmetic operations used in each linear expression.
From the information given:
a. $18.79 + $2.11 + ‐$1.92 + $17.28
By rearrangement:
= $18.79 + $2.11 + $17.28 ‐$1.92
= $36.26
b. $7.45 + ‐$24.45 + $74.17 + ‐$76.52
By rearrangement:
= $7.45 + $74.17 ‐ $24.45 ‐ $76.52
= -$19.35
c. $98.45 − $10.63 + $2.82 − $20.26
By rearrangement:
= $98.45 + $2.82 − $10.63 − $20.26
= $70.38
Learn more about solving linear expressions here:
brainly.com/question/2030026
#SPJ1
<span>sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
<span>
</span><span>
</span>
the solutions to a general quadratic equation is
X=-b±√b²-4ac/2a ,, When ax²+bx+c=0
the discriminant is the expression under the radical b²−4ac
Part A:
discriminant is (-16)² - 4(9)(60) = -1904
there are two complex solutions
Part B:
4x² + 8x − 5 = 0
4x² + 10x -2x - 5=0
2x ( 2x + 5) - 1(2 x + 5) =0
(2x + 5)(2x-1) = 0
/ \
/ \
2x+5 = 0 2x-1 =0
x = -5/2 x = 1/2
Answer:
$2234.26
Step-by-step explanation:
The formula is ...
i = Prt
Filling in the numbers, we have ...
i = $63000·0.11·(118/366) ≈ $2234.26
The year beginning Jan 16, 2012 and ending on the same date in 2013 has 366 days, so we use that for the number of days in the year. Similarly, the day Feb 29, 2012 adds one day to the interest-earning period, so there are a total of 118 days between 1/16/2012 and 5/13/2012.