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navik [9.2K]
3 years ago
10

What is (3 - 3i)(-5 - 4) in the form a + bi?​

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

-27+27i

Step-by-step explanation:

you are trying to simplify this and have to follow pemdas and rearrange it into a+bi form

Ulleksa [173]3 years ago
4 0

Answer:

Hey

Step-by-step explanation:

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Convert 3500 meters into yards. Round your answer to the nearest whole number.​
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yesss a 3500 = 5066

Step-by-step explanation:

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Step-by-step explanation:

10(3)+2(10)(4)+2(3)(4)=30+80+24

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Jim did 35 push-ups on Saturday, 42 push-ups on Sunday, 49 push-ups on Monday, and 56 push-ups on Tuesday. What kind of sequence
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2 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
3 years ago
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