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inna [77]
2 years ago
15

Solve the problem c=3.14d for d

Mathematics
1 answer:
Maksim231197 [3]2 years ago
3 0

Answer:

c = 3.14d \\ d =  \frac{c}{3.14}

It's change of subject. :)

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In a function, y varies inversely with x. The constant of variation is 4. Which table could represent the function?
Colt1911 [192]
I don't see a table but I can give you the means to answer it yourself.  The inverse function is represented by this: y= \frac{k}{x} where k is your constant.  You are given a k value of 4.  If you solve this for k then you will get xy=4.  In your tables, multiply your x value by your y value within your coordinate points and if you get a product of 4 each time you multiply x by y, then that table is your answer.
8 0
3 years ago
Express 0.00048 in scientific notation. hintx
Olenka [21]
(number less tan 10 and more than or equal to 1) times (10^m)

0.00048=4.8 times 10^4

answer si 4.8*10^4
6 0
3 years ago
X
Oxana [17]
I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct
3 0
3 years ago
Factor completely 5x2 – 50x + 120
zaharov [31]
The answer is 5(x - 4)(x - 6)
 
5x² – 50x + 120 = 5*x² -  5*10x + 5*24
                           = 5(x² - 10x + 24)
                           = 5(x * x - 4x - 6x + 6*4)
                           = 5(x(x - 4) - (6x - 6*4))
                           = 5((x(x - 4) - 6(x - 4))
                           = 5(x - 4)(x - 6)
5 0
3 years ago
Class A has 11 pupils and class B has 15 pupils.
Pavlova-9 [17]

Answer:

The mean score in the math test for class B=28.47

Step-by-step explanation:

<em>Step 1: Determine the total number of students in both Classes</em>

Total number of students=number in class A+number in class B

where;

number in class A=11 pupils

number in class B=15 pupils

replacing;

Total number of students=11+15=26 students

<em>Step 2: Determine total score for both classes</em>

Total score for both classes=total score for class A+total score for class B

total score for both classes=mean score for both classes×total number of students

total score for both classes=(49×26)=1,274

total score for class A=mean score for class A×total number of class A students

total score for class A=(77×11)=847

total score for class B=mean score for class B×total number of class B students

total score for class B=m×15=15 m

replacing;

1,274=847+15 m

15 m=1,274-847

15 m=427

m=427/15=28.47

The mean score in the math test for class B=28.47

7 0
3 years ago
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