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inna [77]
3 years ago
15

Solve the problem c=3.14d for d

Mathematics
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

c = 3.14d \\ d =  \frac{c}{3.14}

It's change of subject. :)

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can you guys try to use only 4 fours in this operation ( multiplication, brackets ,addition, subtraction, division and can you f
Readme [11.4K]

9514 1404 393

Answer:

  not possible

Step-by-step explanation:

Among the first 20 natural numbers, the numbers 10, 11, 13, 14, 18, 19 are not possible to make using four 4s and the four basic arithmetic operations.

__

Below are listed the numbers that can be made and one possible way to do it.

{1, ((4*4)/4)/4}, {2, (4/(4+4))*4}, {3, ((4*4)-4)/4}, {4, ((4-4)*4)+4},

{5, ((4*4)+4)/4}, {6, ((4+4)/4)+4}, {7, (4-(4/4))+4}, {8, ((4*4)-4)-4},

{9, ((4/4)+4)+4}, {12, (4-(4/4))*4}, {15, (4*4)-(4/4)}, {16, ((4*4)*4)/4},

{17, (4*4)+(4/4)}, {20, ((4/4)+4)*4}

7 0
3 years ago
He then unpacked 192 packs of frozen peas from 8 boxes. How many packs of frozen peas were in each box?
-Dominant- [34]
You need to divide 192 by 8 to get the amount of frozen peas in 1 box.

192 divided by 8 is equal to 24.

Therefore, in each box, there are 24 peas.
7 0
4 years ago
15 foot circumference equals what diameter
lyudmila [28]
Hi there!

πd = Circumference of th' circle

\dfrac {22}{7} × d = 15 ft

d = 15 × \dfrac {7}{22}

d = \dfrac {105}{22}

d = 4. 77

Hence, the required dia-meter = 4. 77

~ Hope it helps!
7 0
3 years ago
Read 2 more answers
What does each part of an exponential function represent?*<br> f(x) = a(b)* + k
Sergeeva-Olga [200]
A asymptote
b growth/decay
c initial amount
8 0
3 years ago
A Boxer. needs to lose 3 1/2 kg in a month to be able to complete as a flyweight. In three weeks he lowers his weight from 55.5
Airida [17]

Answer: The boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

Step-by-step explanation:

Since we have given that

Quantity of weight a boxer needs to lose in a month is given by

3\frac{1}{2}\ kg\\\\=\frac{7}{2}\ kg=3.5\ kg

In 3 months, he lowers his weight from 55.5 kg to 53.8 kg.

So, Quantity of weight he lose in three months is given by

55.5-53.8\\\\=1.7\ kg

Number of kilograms the boxer lose in the final week to be able to compete as a flyweight is given by

3.5-1.7\\\\=1.8\ kg

Hence, the boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

4 0
3 years ago
Read 2 more answers
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