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Gala2k [10]
1 year ago
12

Let g(x) = f(x+3) for some function f(x). Is g(x) a function? From the previous problem, let the domain of f(x) be [1, 4). What

is the domain of g(x)?
Mathematics
1 answer:
padilas [110]1 year ago
7 0

The domain of g(x) is [4, 7)

<h3>How to determine the domain of g(x)?</h3>

The function is given as:

g(x) = f(x + 3)

Since f(x) is a function, then g(x) is also a function

The domain of f(x) is given as:

[1, 4)

The equivalent of these values in g(x) are

x = 1 + 3 = 4

x = 4 + 3 = 7

Hence, the domain of g(x) is [4, 7)

Read more about domain at

brainly.com/question/1770447

#SPJ1

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Original - New / Original
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6 0
3 years ago
If 2x − 4(x + 1) = −12, evaluate x2 − 1.
Vlad [161]
2x-4(x+1)=-13
1) we solve this equation:
2x-4(x+1)=-12
2x-4x-4=-12
-2x=-12+4
-2x=-8
x=-8/-2
x=4

2) we evalute x²-1
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Answer: 15
6 0
3 years ago
Analyze the diagram below and complete the instructions that follow?
yan [13]

Answer:

The exact value of tan(M) is 5/12 ⇒ answer (C)

Step-by-step explanation:

* Lets revise the trigonometry functions

- In ΔABC

# m∠B = 90°

# Length of AB = a , length of BC = b and length of AC = c

# The trigonometry functions of angle C are

- sin(C) = a/c ⇒ opposite side to ∠C ÷ the hypotenuse

- cos(C) = b/c ⇒ adjacent side to ∠C ÷ the hypotenuse

- tan(c) = a/b ⇒ opposite side to ∠C ÷ adjacent side to ∠C

* Now lets solve the problem

- In ΔONM

∵ m∠N = 90°

∵ MN = 12

∵ ON = 5

∵ tan(M) = ON/NM ⇒ opposite side of ∠(M) ÷ adjacent side of ∠(M)

∴ tan(M) = 5/12

* The exact value of tan(M) is 5/12

6 0
3 years ago
I need help I don't understand this
kaheart [24]
What part do you not understand?
7 0
2 years ago
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