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Veseljchak [2.6K]
3 years ago
8

I need the mean, medium, and the mode for these numbers [4,10,11,15,16,16,18,19]​

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Hello here would be your answers:

mean: 13.6  

mediun: 15.5  

mode: 16

remember it like this

Mean is the average

Mode is the most often number

Range is when you subtract the smallest number from the largest number

Medium is the middle number when you line it up from the greatest to the least.

hope this helps!

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Answer:

why isn't life reeeeeeeeeeeeeee

Step-by-step explanation:

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3 years ago
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german
Teresa has 19, Manual has 57, and John has 25

Here’s how to do it:

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3 years ago
Thank you now help please
swat32
If it is #17 this:

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3 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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Write an equation to find the total number of hours h the instructor exercises in any number of weeks w
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Have a pic of the problem?
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