I’m pretty sure the equation would be
2x + 13 < 3x - 2
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)
so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
Answer:
sinceramente no entiendo tu idioma.... sprry me encantaria poder ayudarte pero bvueno espero que consigas una respuesta rapida y efectiva no como la mia que fue tan inutil bye
Step-by-step explanation:
Answer:
x = HJ/5 + 3/5
HJ = 5x - 3 = 5 (11) - 3 = 55 - 3 = 52
JK = 8x - 9 = 8(11) - 9 = 88 - 9 = 79
Answer:
what I dont even know whT your talking about. could you please explain your question a bit more?? then maybe I could help you out
