Find the orthocenter of △ABC. A(2, 3), B(−4, −3), C(2, −3)
1 answer:
ANSWER
EXPLANATION.
The orthocenter is the point of intersection of any two altitudes of the triangle.
First, you need to determine the slope of each side of the triangle.
△ABC has vertices A(2, 3), B(−4, −3), C(2, −3).
This line has undefined slope, which means it is a vertical line.
The slope of this line is zero, meaning the line is a horizontal line.
This implies that side BC and side AC of the given triangle are perpendicular and will intersect at C since they are the altitudes of triangle ABC.
Hence the orthocentre is
See diagram in attachment.
EXPLANATION.
The orthocenter is the point of intersection of any two altitudes of the triangle.
First, you need to determine the slope of each side of the triangle.
△ABC has vertices A(2, 3), B(−4, −3), C(2, −3).
This line has undefined slope, which means it is a vertical line.
The slope of this line is zero, meaning the line is a horizontal line.
This implies that side BC and side AC of the given triangle are perpendicular and will intersect at C since they are the altitudes of triangle ABC.
Hence the orthocentre is
See diagram in attachment.
You might be interested in
The attached graph represents the graph of f(x) = (x - 1)^2 - 2
<h3>How to plot the graph?</h3>The equation is given as:
f(x) = (x - 1)^2 - 2
Next, we set x to -2, -1, 0, 1 and 2.
So, we have:
f(-2) = (-2 - 1)^2 - 2 = 7
f(-1) = (-1 - 1)^2 - 2 = 2
f(0) = (0 - 1)^2 - 2 = -1
f(1) = (1 - 1)^2 - 2 = -2
f(2) = (2 - 1)^2 - 2 = -1
This means that the table of values is
x f(x)
-2 7
-1 2
0 -1
1 -2
2 -1
Next, we plot the above points and connect them.
See attachment for the graph of f(x) = (x - 1)^2 - 2
Read more about graphs and functions at:
#SPJ1
