Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
x=4
Step-by-step explanation:
4(3+2x)+2=46
12+8x+2=46
12+8x=44
8x=32
x=4
Answer:
27
Step-by-step explanation:
r = 9
s = 6
r^2
= r x r
= 9 x 9
= 81
13s
= 13 x 6
= 108
13s - r^2
= 108 - 81
= 27
It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation
Answer:
x = 18
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
x+x+x=54
(x+x+x)=54(Combine Like Terms)
3x=54
3x=54
Step 2: Divide both sides by 3.
3x 3
=
54
3
x=18
Answer:
x=18
