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iragen [17]
3 years ago
15

Which function has real zeros at x = 3 and x = 7?

Mathematics
2 answers:
sineoko [7]3 years ago
8 0
F(x) = (x - 3)(x - 7)
expanding the brackets gives:
f(x) = x^2 - 10x + 21
oksian1 [2.3K]3 years ago
8 0

Answer:

f(x) = x² - 10x + 21

Step-by-step explanation:

Functions that has real zeros at x = 3 and x = 7 are the function that produces the roots of 3 and 7 after factorising.

Having two roots as given;

x = 3 and

x = 7

If x=3 then x -3 = 0... 1

Similarly;

If x = 7 then x-7 = 0... 2

Multiplying the zero functions in equation 1 and 2 together we have;

f(x) = (x-3)(x-7)

f(x) = x²-7x-3x+21

f(x) = x² - 10x + 21 = 0

The polynomial or quadratic function above gives the required function.

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Solve for x in the diagram below
ella [17]

Answer:

20

Step-by-step explanation:

3x + x + 100 = 180 (sum of angles on a straight line)

4x = 180-100

4x=80

divide both sides by 4

x=20

8 0
3 years ago
Find the center and the radius of the circle given this equation:<br> 2<br> x + 4x + y ² -10y +20=0
NemiM [27]

Answer:

vertex: (5/6,5)

focus: (- 2/3, 5)

axis of symmetry: y = 5

directrix: x = 7/3

Step-by-step explanation:

use the vertex form to determine the values of a.h. and k and use these values to find the direction the parabola opnes, vertex, foucs, axis of symmetry, and directrix

5 0
3 years ago
A quiz has 5 questions with answers that are either true or false. How many different combinations of answers are possible?
bearhunter [10]
I believe 6 because either
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4 0
4 years ago
Read 2 more answers
F(x)=6(1-x) what is the value of f(-8)
Mariulka [41]

Answer:

54

Step-by-step explanation:

What the shorthand is telling you is wherever you see an x on the right, you put in -8

f(x) = 6(1- x)

f(-8) = 6(1 - - 8)

f(-8) = 6(1+8)

f(-8) = 6*9

f(-8) = 54

8 0
3 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
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