Question

The distance d in feet that a dropped odie tu falls in t seconds is given by the square d divided 16=t^2.How long does it take a dropped object to fall 64 feet

Answer 1

Answer:

The correct answer is 16 seconds for the body to fall 64 feets.

Step-by-step explanation:

The equation of a dropped odie tu falling is given by $\frac{d^{2}}{16} = t^{2}$ where d is the distance in feet and t is the time it took in seconds.

Now an object falls from 64 feet. The time it takes to fall is given by

$\frac{64^{2}}{16}$ = $t^{2}$

⇒ t = ± $\frac{64}{4}$ = 16.

Negative sign is neglected as time cannot be negative.

Thus it would take 16 seconds for the object to drop from 64 feets.