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Sladkaya [172]
3 years ago
10

Apples are 0.99 lb someone buys 8.9 pounds of apples and has 10dollors how much will she get back

Mathematics
1 answer:
artcher [175]3 years ago
4 0
The apples would cost (8.9x.99) $8.81. So, 10-8.81 is about 1.19. They would get $1.19 back
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Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd
lora16 [44]

The logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Given to us

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

<h3>Which expression is equivalent to \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} ?</h3>

To solve the problem we will use the basic logarithmic properties,

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

Using the logarithmic property \rm log_a\dfrac{x}{y} = log_ax-log_ay,

=\rm log_w{(x^2-6)^4} - log_w{\sqrt[3]{x^2-8}}

Using the exponential property \sqrt[m]{a^n} = a^{\frac{n}{m}},

=\rm log_w{(x^2-6)^4} - log_w(x^2-8)^{\dfrac{1}{3}}

Using the logarithmic property \rm log_aB^x = xlog_aB,

=\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)

Hence, the logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Learn more about Logarithmic Expression:

brainly.com/question/7302008

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3 years ago
Help please I need to turn it in
Alinara [238K]

Answer:

7.C

9.C

10.6x+5=15

Step-by-step explanation:

7 is trying to trick you. You have to divide 43.20 by 5 instead of 4. They split the tickets, but they gave some to her too.

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Man I wish I had your homework.

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