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steposvetlana [31]
3 years ago
13

Sea World has 9 aquariums with small fish in them and the number of fish in each tank are shown below: 45, 10, 48, 19, 36, 25, 6

3, 14, 37 What is the range of the number of fish?
Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer:

53

Step-by-step explanation:

To find the range, subtract the lowest number from the highest number

Arrange the numbers from least to greatest

45, 10, 48, 19, 36, 25, 63, 14, 37

10, 14, 19, 25, 36, 37, 45, 48, 63

The highest number is 63, and the lowest is 10

Now, subtract the lowest (10) from the highest (63)

highest - lowest

63-10

53

So, the range of the number of fish is 53

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(x+d)(x+e)=x^2+fx+33
victus00 [196]

Answer:

f=14 or f=34

Step-by-step explanation:

(x+d)(x+e) =x^2 +fx+33, d, e, f>0

x^2 +xe+dx+de=x^2+fx+33

x^2+(e+d)x+de=x^2 +fx+33 that

e+d=f and d*e=33, d=33/e

e+33/e=f

33=1*33 or 33=3*11

If e=1,d=33 then f=34

If e=3*,d=11, then f=14

4 0
3 years ago
What is the coordinate of point P on the line segment AB that is 3/4 of the distance from A to B for A(2,5) and B(6,9)?
Brut [27]

Answer:

p  is (3.71, 6.71)

Step-by-step explanation:

Given that p is at the distance of 3/4 from A to B

it mean that point p divides the line AB into 3:4 ratio.

and

if there are two points (x1,y1) and (x2,y22) which is divided by point p in the ratio m:n then

coordinates of point p (x,y) is given

p (x = (n*x1+m*x2)/m+n , y = (n*y1+m*y2)/m+n )

________________________________________________

Given the points AB

A(2,5)

B(6,9)

m:n = 3:4

thus,

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (4*2+3*6)/7 , y = (4*5+3*9)/7 )

p (x = (26/7 , y = 47/7 )

P ( x = 3.71, y = 6.71)

Thus, coordinates of point p  is (3.71, 6.71) which is  at  3/4 of the distance from A to B for A(2,5) and B(6,9)/

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Step-by-step explanation:

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3 years ago
Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of people who write wit
SCORPION-xisa [38]

Answer:

Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.

Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.

Step-by-step explanation:

We are given the following hypothesis below;

Let p = <u><em>proportion of people who write with their left hand</em></u>

So, Null Hypothesis, H_0 : p = 0.22     {means that the proportion of people who write with their left hand is equal to 0.22}

Alternate Hypothesis, H_A : p \neq 0.22      {means that the proportion of people who write with their left hand is different from 0.22}

Now, Type I error states that we conclude that the null hypothesis is rejected when in fact the null hypothesis was actually true. Or in other words, it is the probability of rejecting a true hypothesis.

So, in our question; Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.

Type II error states that we conclude that the null hypothesis is accepted when in fact the null hypothesis was actually false. Or in other words, it is the probability of accepting a false hypothesis.

So, in our question; Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.

4 0
2 years ago
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