9(2w−y)=21w−9y
First you multiply the numbers in the parenthesis by 9
subtract. 21w-18w=3w
add. -9y+9y=0
divide.
Final answer is 0.
A spinner is divided into 8 equal sections. Two of the sections are red, 3 are green, and 3
1 answer:
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Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:
Compute the probability that none of the LED light bulbs are defective as follows:
Thus, the probability that none of the LED light bulbs are defective is 0.7374.