Answer:
The equation of the graphed line is:
Step-by-step explanation:
From the graph, it is clear that the line is a horizontal line at y = 2.
We know that a horizontal line has a slope of 0 because the value of y does not change no matter what the value of x we put in.
In other words, the equation of the horizontal line would always get the form:
y = k
where k is the y-intercept of the line.
Determining the y-intercept of the line:
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept k = 2
Thus, if we substitute the y-intercept k = 2 in the equation y = k, we get the equation
y = 2
Therefore, the equation of the graphed line is:
Answer:
mB = 113 degrees
Step-by-step explanation:
180 - 67 = 113
Answer:
1.) ax2+Bx+c
2.) parabola
3.) I don't know
4.) I don't know
5.) maximum
6.) minimum
7/8) The solutions of a quadratic equation are also called roots, zeroes, and x -intercepts.
I hope this kinda helped.
The coordinate of the circumcenter of a triangle is (1,3).
Here we have to find the coordinates of the circumcenter of a triangle.
Given data:
The vertices of the triangle are:
A = (0,1)
B = ( 2,1)
C= ( 2,5)
The formula to find the distance between the two points:
Distance = ![\sqrt{(x2 - x1)^{2} + (y2-y1)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x2%20-%20x1%29%5E%7B2%7D%20%2B%20%28y2-y1%29%5E%7B2%7D%20%7D)
In the same manner distance between AB, BC, and AC are:
AB = ![\sqrt{(2-0)^{2} + (1-1)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%282-0%29%5E%7B2%7D%20%2B%20%281-1%29%5E%7B2%7D%20%20%7D)
= 2
BC = ![\sqrt{(2-2)^{2} + (5-1)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%282-2%29%5E%7B2%7D%20%2B%20%285-1%29%5E%7B2%7D%20%20%7D)
= 4
AC = ![\sqrt{(2-0)^{2} + (5-1)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%282-0%29%5E%7B2%7D%20%2B%20%285-1%29%5E%7B2%7D%20%7D)
= 2√5
So by the Pythagoras, we get to know that the triangle is a right-angle triangle.
The circumcenter of a right-angle triangle is the midpoint of the hypotenuse.
Midpoint of AC = (0+2)/2 , (1+5)/2
= 2/2, 6/2
= 1,3
Therefore the coordinate of the circumcenter is (1,3).
To know more about the circumcenter refer to the link given below:
brainly.com/question/21299234
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