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kari74 [83]
3 years ago
11

Identify the graphical solution to the inequality

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Answer:

A

Step-by-step explanation:

to solve absolute value inequalities you must solve it for when the absolute value is positive and then when it is negative

example, |4| = 4 and -4

first solution will be when we're solving for the positive value:

+(-4x+7) ≥ 27

-4x + 7 ≥ 27

-4x ≥ 20

x ≤ -5   [reverse the symbol when mult or div by a negative]

-(-4x+7) ≥ 27

4x - 7 ≥ 27

4x ≥ 34

x ≥ 34/4 or x ≥ 8 1/2

solution:  x ≤ -5 or x ≥ 8.5

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Which theorem or postulate proves that triangle ABC and triangle DEF are similar?
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Answer:

sss

Step-by-step explanation:

to get from the triangle on the left to the one on the right, you multiply each corresponding side on the smaller triangle by 6

The answer is SSS similarity theorem.

8 0
3 years ago
Customers' sandwich choices one day at ray's lunch counter are shown.
oee [108]

If you read the question you can find that some requirements were missing. By Googling the Question the complete content could be found here:

https://www.chegg.com/homework-help/questions-and-answers/ved-restore-nu-sge-essments-testnavaspx-idassessment-1591215-idwebuser-30156018idsection-1-q44055003

The relative frequencies missing in the table are :

ham-wheat = 0.231, cheese-wheat = 0.0.462.

rye-turkey = 0.167, rye-ham = 0.417.

<u> Step-by-step explanation: </u>

From the given data we have to count the frequencies of wheat and rye chosen to find the missing values.

The frequency of wheat chosen = 13.

The frequency of rye chosen = 12.

Relative Frequency can be obtained by dividing the combined frequency by the total number of data values.

Wheat combinations:

1) The frequency of ham-wheat = 3.

Then the relative frequency of ham-wheat = \frac{3}{13}.

The the relative frequency of ham-wheat = 0.230769 or 0.231.

2) The frequency of cheese-wheat = 6.

Then the relative frequency of cheese-wheat = \frac{6}{13}.

The the relative frequency of cheese-wheat = 0.4615 or 0.0.462.

Rye combinations:

1) The frequency of rye-turkey = 2.

Then the relative frequency of rye-turkey = \frac{2}{12}.

The the relative frequency of rye-turkey = 0.1666 or 0.167.

2) The frequency of rye-ham = 5.

Then the relative frequency of rye-ham = \frac{5}{12}.

The the relative frequency of rye-ham = 0.41667 or 0.417.

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3 years ago
WILL MARK YOU BRAINLIEST, PLEASE HELP!!!
lutik1710 [3]

Given:ABCD is a rhombus.

To prove:DE congruent to BE.

In rombus, we know opposite angle are equal.

so, angle DCB = angle BAD

SINCE, ANGLE DCB= BAD

SO, In triangle DCA

angle DCA=angle DAC

similarly, In triangle ABC

angle BAC=angle BCA

since angle BCD=angle BAD

Therefore, angle DAC =angle CAB

so, opposite sides of equal angle are always equal.

so,sides DC=BC

Now, In triangle DEC and in triangle BEC

1. .DC=BC (from above)............(S)

2ANGLE CED=ANGLE CEB (DC=BC)....(A)

3.CE=CE (common sides)(S)

Therefore,DE is congruent to BE (from S.A.S axiom)

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